/*
 * ECHO -- print arguments followed by a newline
 *
 * Usage: echo arg1 arg2 ... argn
 *
 * Options:	-n	suppress trailing newline
 * Inputs: none
 * Outputs: the non-option arguments except for the 0th (which is the program
 * name), separated by a blank, and (optionally) with a newline at the end 
 * Exceptions: if no arguments beyond the program name, do not output a newline
 *
 * Exit Code: EXIT_SUCCESS
 *
 * Matt Bishop, ECS 36A, Fall 2019
 *
 * Oct. 22, 2015 -- original program written
 * Oct. 23, 2019 -- modified for ECS 36A
 */
#include <stdio.h>
#include <string.h>

/*
 * the main routine
 */
int main(int argc, char *argv[])
{
	int prnl = 1;		/* 1 to print newline, 0 not to */
	int i = 1;			/* counter in a for loop */

	/*
	 * if argument 0 is -n, set prnl to suppress newline
	 * skip it in the printing; otherwise, print beginning with arg 1
	 */
	if (argc > 1 && strcmp(argv[1], "-n") == 0){
		/* suppress the newline */
		prnl = 0;
		/* start printing at arg[2] */
		i = 2;
	}
	/*
	 * go through the argument list, skipping arg 0 (it's
	 * the program name) and arg 1 if needed
	 */
	for( ; i < argc-1; i++)
		printf("%s ", argv[i]);
	/*
	 * now print the last argument, UNLESS it is arg 0, or arg 1 and -n
	 */
	if (argc > 1 && (argc != 2 || prnl))
		printf("%s", argv[argc-1]);
	/*
	 * put out the newline if appropriate
	 */
	if (prnl && argc > 1)
		putchar('\n');
	/*
	 * return success!
	 */
	return(0);
}