/*
 * add 2 to j 100 times
 *
 * this program has a bug -- comments omitted to hide it
 * used to demonstrate static and dynamic debugging
 *
 * Matt Bishop, ECS 36A, Fall 2019
 */
#include <stdio.h>

int main(void)
{
	int i, j = 0;

	for(i = 0; i < 100; i++);
		j += 2;

	printf("The value of j is: %d\n", j);
	return(0);
}