/*
 * WC -- program to count characters, words, and lines in the input
 *
 * Usage: wc
 *
 * Inputs: text to count characters, words, lines
 * Output: character, word, line counts
 * Exit Code: EXIT_SUCCESS (0) because all goes well
 *
 * Approach:
 * counting characters: increment char counter after each char is read
 * counting lines: increment line counter after each '\n' is read
 * counting word: initially, start not in word; when you read a non-
 * 	space, enter word and increment word counter; when you read a
 * 	space, leave word (so you are not in word); repeat until enf
 * 	of file read
 *
 * Matt Bishop, ECS 36A, Fall 2019
 * October 12, 2019: modified from a program written for ECS 30
 */

#include <stdio.h>
#include <stdlib.h>

#define IN_WORD		1	/* currently inside a word */
#define NOTIN_WORD	0	/* currently not in a word */

/*
 * count the number of lines, words, and chars in the input
 * a word is a maximal sequence of nonspace characters, so
 * the quote "+++ --- hi bye 879+3" has 5 words ("+++", "---",
 * "hi", "bye", and "879+3")
 */
int main(void)
{
	int c;		/* input char */
	int nl;		/* line count */
	int nw;		/* word count */
	int nc;		/* char count */
	int state;	/* in or not in a word? */

	/*
	 * initialize
	 */
	nl = nw = nc = 0;
	state = NOTIN_WORD;

	/*
	 * handle input a char at a time
	 */
	while((c = getchar()) != EOF){
		/* got another character */
		nc++;
		/* is it a newline? */
		if (c == '\n')
			nl++;
		/* is it a word separator? */
		if (c == ' ' || c == '\t' || c == '\n')
			/* YES -- change state */
			state = NOTIN_WORD;
		else if (state == NOTIN_WORD){
			/* NO -- we're now in a word; update */
			/* the counter and state if need be  */
			state = IN_WORD;
			nw++;
		}
	}

	/*
	 * announce the results and quit
	 */
	printf("%6d\t%6d\t%6d\n", nl, nw, nc);
	exit(EXIT_SUCCESS);
}