/*
* add 2 to j 100 times
*
* this program has a bug -- comments omitted to hide it
* used to demonstrate static and dynamic debugging
*
* Matt Bishop, ECS 36A, Fall 2019
*/
#include <stdio.h>
int main(void)
{
int i, j = 0;
for(i = 0; i < 100; i++);
j += 2;
printf("The value of j is: %d\n", j);
return(0);
}
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ECS 36A, Programming & Problem Solving Version of April 2, 2024 at 12:13PM
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You can get the raw source code here. |